Cruising_Adventuring Posted November 10, 2005 Author Share Posted November 10, 2005 Here is another fun little problem for all your guys that want to try it out. Also would you rather th answer be the coordinates, or would you want to e mail me and i would e mail you back a hint if it was wrong or i would give you coordinates if it was right? *Neglect all air frictions* *Gravity is 9.8m/s^2* *The rocket doesnt pass through the atmosphere.* *Keep it simple* Ok a rocket is traveling at +155m/s, it is decelerated at a rate of -31m/s^2. A. How long will it take before the instantaneous speed is 0 m/s? B. How far will it travel during this time? C. What will be its velocity after 8.0s? Try this out if you want! Quote Link to comment
+jwigner Posted November 10, 2005 Share Posted November 10, 2005 As for me, I'd be taking at least one derivative. I didn't make it all the way through differential equations for nothing. Now, let's see... y(t) = position y'(t) = velocity y"(t) = acceleration y'"(t) = jerks... Quote Link to comment
+GSVNoFixedAbode Posted November 11, 2005 Share Posted November 11, 2005 The answer? 42 Well, someone had to say it. Quote Link to comment
+Ladybug Kids Posted November 11, 2005 Share Posted November 11, 2005 (edited) A: 5 seconds B: +387.5 m C: -93 m/s Here's another for all you Physics Phanatics: Hole in One! Edited November 11, 2005 by Ladybug Kids Quote Link to comment
+Jellyfishman Posted November 11, 2005 Share Posted November 11, 2005 Honestly, who drops their tools from anything flying? Do all the math you want. the solution is "LOST!" Jelly Quote Link to comment
TCE Posted November 11, 2005 Share Posted November 11, 2005 Would there be a downdraft due to the helicopter's blades spinning? Is the wrench the flat kind that might be influenced by wind?...or a big lug monkey kind of wrench? I have no idea about any kind of physics type problems...but those might be somethings to consider... Quote Link to comment
Cruising_Adventuring Posted November 11, 2005 Author Share Posted November 11, 2005 Would there be a downdraft due to the helicopter's blades spinning? Is the wrench the flat kind that might be influenced by wind?...or a big lug monkey kind of wrench? I have no idea about any kind of physics type problems...but those might be somethings to consider... It would be just a normal wrench, however it doesnt matter what type of wrench it is because when neglecting all frictions, the wrench would behave like a feather, a rock, a pencil, a toothbrush, a tb, whatever because they all fall at the same acceleration on earth, 9.8m/s/s. this means after 2 second it isnt falling 9.8 m/s it would be falling 19.6 m/s and so on. When physics states to ignore all frictions its like your in space, (besides the 9.8m/s/s gravity force) it is a vacuum where on the moon astronaughts dropped a feather and a hammer and they landed at the same time. -Those calculations posted above were correct too. Nice job. Quote Link to comment
+dykediva Posted November 11, 2005 Share Posted November 11, 2005 A wrench falls from a helicopter that is rising steadily at +6.0 m/s. After 2.0s a. what is the velocity of the wrench? b. how far below the helicopter is the wrench? ARE YOU SERIOUS?? I can barely balance my checkbook. . .Physics wooo hoooo that is too funny. . .I really think you are yanking my chain. Let me just ask Number One to slow the Enterprise way down so Jordy can help me answer that question before the warp core reactor blows. . . . Quote Link to comment
Cruising_Adventuring Posted November 11, 2005 Author Share Posted November 11, 2005 ok here are all of the calculations for the rocket problem. Go easy on me i suck at explaining things, hey im only 16... A.... Vf=0 Vi=155m/s a=-31m/s So i will use the formula a=Vf-Vi/a i changed it to t=Vf-Vi/a so t=0-155/-31 so.... t=5 seconds __________________________________________________________________ B...... Vf=0 Vi=155m/s a=-31m/s t=5s d=? Vf^2=Vi^2+2ad so i changed it to -Vi^2=2ad -155^2=2(-31)d -24025=-62d so d=387.5 ____________________________________________________________________ Finally on to part C...... Vi=155m/s a=-31m/s^2 t=8s Vf=? Vf=Vi+at so lets add the numbers now.... Vf=155+(-31)(8) so Vf=-93m/s believe it or not here was one way you could of done the calculations to find the answer. Quote Link to comment
Cruising_Adventuring Posted November 11, 2005 Author Share Posted November 11, 2005 Here is a problem related to GC You first walk 8.0km North from your home to get the FTF on a new geocache. Then walk East (to avoid some poisn oak) until your distance from home is 10.0km How far east did you walk.?? its alot easier to draw a picture on this one and to use pythagoream thereom ....a^2+b^2=c^2 Hey but seriously if you got lost you could use something like this to arrive home safely. lol Quote Link to comment
+ParrotRobAndCeCe Posted November 11, 2005 Share Posted November 11, 2005 Here is a problem related to GC You first walk 8.0km North from your home to get the FTF on a new geocache. Then walk East (to avoid some poisn oak) until your distance from home is 10.0km How far east did you walk.?? its alot easier to draw a picture on this one and to use pythagoream thereom ....a^2+b^2=c^2 Hey but seriously if you got lost you could use something like this to arrive home safely. lol 6k. It's a simple 3-4-5 right triangle. OK, Cruising, here's one for you, and only you (so all you wily types hush up): You head out to look for my new multi-cache. After arriving at the posted coordinates, you find instructions telling you to walk 1km DUE SOUTH to the next waypoint. This waypoint instructs you to walk 1km DUE EAST to find the next waypoint. At this waypoint, you are told to walk 1km DUE NORTH, which you then do. Amazingly, you find yourself at exactly the same place you started. How is this possible? Quote Link to comment
+Right Wing Wacko Posted November 11, 2005 Share Posted November 11, 2005 The answer? 42 Well, someone had to say it. I'm glad I read the whole thread before posting.... that was going to be MY answer! Quote Link to comment
+Right Wing Wacko Posted November 11, 2005 Share Posted November 11, 2005 Here is a problem related to GC You first walk 8.0km North from your home to get the FTF on a new geocache. Then walk East (to avoid some poisn oak) until your distance from home is 10.0km How far east did you walk.?? its alot easier to draw a picture on this one and to use pythagoream thereom ....a^2+b^2=c^2 Hey but seriously if you got lost you could use something like this to arrive home safely. lol 6k. It's a simple 3-4-5 right triangle. OK, Cruising, here's one for you, and only you (so all you wily types hush up): You head out to look for my new multi-cache. After arriving at the posted coordinates, you find instructions telling you to walk 1km DUE SOUTH to the next waypoint. This waypoint instructs you to walk 1km DUE EAST to find the next waypoint. At this waypoint, you are told to walk 1km DUE NORTH, which you then do. Amazingly, you find yourself at exactly the same place you started. How is this possible? ooo...oooo.... I know the coordinates of that cache! Quote Link to comment
+fizzymagic Posted November 11, 2005 Share Posted November 11, 2005 You first walk 8.0km North from your home to get the FTF on a new geocache. Then walk East (to avoid some poisn oak) until your distance from home is 10.0km How far east did you walk.?? its alot easier to draw a picture on this one and to use pythagoream thereom ....a^2+b^2=c^2 It's too bad that the Pythagorean theorem only works on planes, and the Earth is a sphere, huh? Because it makes your solution incorrect. Are you interested in the actual correct answer? Quote Link to comment
Cruising_Adventuring Posted November 11, 2005 Author Share Posted November 11, 2005 (edited) Here is a problem related to GC You first walk 8.0km North from your home to get the FTF on a new geocache. Then walk East (to avoid some poisn oak) until your distance from home is 10.0km How far east did you walk.?? its alot easier to draw a picture on this one and to use pythagoream thereom ....a^2+b^2=c^2 Hey but seriously if you got lost you could use something like this to arrive home safely. lol 6k. It's a simple 3-4-5 right triangle. OK, Cruising, here's one for you, and only you (so all you wily types hush up): You head out to look for my new multi-cache. After arriving at the posted coordinates, you find instructions telling you to walk 1km DUE SOUTH to the next waypoint. This waypoint instructs you to walk 1km DUE EAST to find the next waypoint. At this waypoint, you are told to walk 1km DUE NORTH, which you then do. Amazingly, you find yourself at exactly the same place you started. How is this possible? actually you would be 1 km of to the EAST from the starting position. 1km l l 1km l l ------------ 1km tried to edit for my stupid box i made but hopefully tou get the point? Edited November 11, 2005 by Cruising_Adventuring Quote Link to comment
Cruising_Adventuring Posted November 11, 2005 Author Share Posted November 11, 2005 You first walk 8.0km North from your home to get the FTF on a new geocache. Then walk East (to avoid some poisn oak) until your distance from home is 10.0km How far east did you walk.?? its alot easier to draw a picture on this one and to use pythagoream thereom ....a^2+b^2=c^2 It's too bad that the Pythagorean theorem only works on planes, and the Earth is a sphere, huh? Because it makes your solution incorrect. Are you interested in the actual correct answer? Thats a very good point, but lets figure that the ground was a plane...lol however, even when figuring out the problem with the added distance due to the earths curve you would have to assume that there are no elevation changes? *hey are you really a physicist?* *if so right on!* Quote Link to comment
+Thrak Posted November 11, 2005 Share Posted November 11, 2005 Have you ever tried Chicken Fat Ripple ice cream? ================================== I wouldn't throw the wrench at you. I'd be afraid I might miss. I would walk up to you and beat you until you were nothing but a puddle of goo and then pour gasoline on the goo and light it on fire. ================================== I hate puzzles like this. Can you tell? (I was a 2/3 "B" and 1/3 "A" math student. I still hate this stuff anyway. This is GEOCACHING - not physics class!) Crap like this can drive folks to drink. Quote Link to comment
Cruising_Adventuring Posted November 11, 2005 Author Share Posted November 11, 2005 I hate puzzles like this. Can you tell? (I was a 2/3 "B" and 1/3 "A" math student. I still hate this stuff anyway. This is GEOCACHING - not physics class!) rofl...well you dd a good job on adding your fractions! 1/3+2/3=1!!! Quote Link to comment
+fizzymagic Posted November 11, 2005 Share Posted November 11, 2005 *hey are you really a physicist?* Yes, indeed. Not only that, but my wife went to Rim Of The World High School. The actual answer to your problem, BTW, is very complicated. Depends on your definition of distance and your definition of "due east." Solve my Neutrino cache. Seriously! You'll learn a lot about measuring distances on and through the Earth while doing a real-life physics problem. Quote Link to comment
Cruising_Adventuring Posted November 11, 2005 Author Share Posted November 11, 2005 I dont get down there to often to where the cache is located....or at least where the map points out it might be, but you can count on my trying to solve this awesome problem! Quote Link to comment
Cruising_Adventuring Posted November 11, 2005 Author Share Posted November 11, 2005 Anyways...I would be interested in your answer to the pythag problem. Quote Link to comment
tttedzeins Posted November 11, 2005 Share Posted November 11, 2005 Honestly, who drops their tools from anything flying? Do all the math you want. the solution is "LOST!" Jelly Please warn before posting those comments. People at work look at me wierdly enough without me bursting out laughing spontaneously. Quote Link to comment
Mushtang Posted November 11, 2005 Share Posted November 11, 2005 actually you would be 1 km of to the EAST from the starting position. Not always. It's possible to be right back where you started. Do you give up? Quote Link to comment
JohnX Posted November 11, 2005 Share Posted November 11, 2005 (edited) actually you would be 1 km of to the EAST from the starting position. Not always. It's possible to be right back where you started. Do you give up? Hmm...... South, East, North? I saw a bear there, but I still don't know what they do in the woods. Does anyone know what color the bear was? Edited to add: The answer is always 42. Edited November 11, 2005 by JohnX Quote Link to comment
+fizzymagic Posted November 11, 2005 Share Posted November 11, 2005 It's possible to be right back where you started. Do you give up? Of course, you understand that this requires a very specific definition of what "due East" means... In this case, the path has to be a rhumb line, which is a path of constant heading.. Quote Link to comment
+Ed & Julie Posted November 11, 2005 Share Posted November 11, 2005 hey everypne i want to do a puzzle cache. Here is an example of a question that i might ask. (if you havent guessed physics is my favorite thing in the world!)...well sorta. A wrench falls from a helicopter that is rising steadily at +6.0 m/s. After 2.0s a. what is the velocity of the wrench? b. how far below the helicopter is the wrench? if you guys could try to solve this it would help me out. Just tell me whether you would do this type of problem to get the coordinates of a cache, or if it takes to much time. ALSO NEGLECT ALL FRICTIONS. (keep it easy) If my finger moves my mouse to the ignore button at .05 miles per hours... Quote Link to comment
rynd Posted November 12, 2005 Share Posted November 12, 2005 I hate to beat a dead horse and you may have already answerd this but: on the hele/wrench thing wouldn't you have to factor in that the wrench is initially moving up with the chopper ? Quote Link to comment
Cruising_Adventuring Posted November 12, 2005 Author Share Posted November 12, 2005 I hate to beat a dead horse and you may have already answerd this but: on the hele/wrench thing wouldn't you have to factor in that the wrench is initially moving up with the chopper ? Well to asnwer that question... The wrench is traveling at 6m/s with the helicopter until it is dropped outside the helicopter, So yes you do need to take that into account. Quote Link to comment
+Kidatheart Posted November 12, 2005 Share Posted November 12, 2005 So which train left what station when I probably would print it out and work on it wjem bored but not right away. Mostly because I have limited time and if I worked it out wrong I would be upset at myself rather then getting a DNF and being made at lack of geo mojo. Quote Link to comment
Cruising_Adventuring Posted November 12, 2005 Author Share Posted November 12, 2005 (edited) Here is another one for all you Physics Buffs out there... Determine the final speed of a proton that has an initial speed of 2.35 x 10^5m/s and then is decelerated uniformly in an electric field at the rate of 1.10 x 10^12m/s^2 for 1.50 x 10^-7 ?? This one isn't really that hard at all, the numbers just make it look scary. edited for spelling Edited November 12, 2005 by Cruising_Adventuring Quote Link to comment
+TeamAO Posted November 12, 2005 Share Posted November 12, 2005 I saw a cache similar to this. I like the idea of when the cache page is like.... A plane at X-Coordinates, flying a X-Bearing, at X mph drops an ammo can out of the plane. Using the information provided and some physics problem one can probably solve for where the cache is. I cannot find the link to the cache that was similar, but I liked the idea. Quote Link to comment
+One of the Texas Vikings Posted November 12, 2005 Share Posted November 12, 2005 I love chicken and donuts. Yes, chicken tastes like cats ! Quote Link to comment
Mushtang Posted November 14, 2005 Share Posted November 14, 2005 It's possible to be right back where you started. Do you give up? Of course, you understand that this requires a very specific definition of what "due East" means... In this case, the path has to be a rhumb line, which is a path of constant heading.. Okay, so change the puzzle to say, "go towards the East pole...." Quote Link to comment
+Airmapper Posted November 14, 2005 Share Posted November 14, 2005 (edited) Somebody said Helicopter!!! You can use my avatar as a visual aid. Edited November 14, 2005 by Airmapper Quote Link to comment
+ParrotRobAndCeCe Posted November 15, 2005 Share Posted November 15, 2005 Here is a problem related to GC You first walk 8.0km North from your home to get the FTF on a new geocache. Then walk East (to avoid some poisn oak) until your distance from home is 10.0km How far east did you walk.?? its alot easier to draw a picture on this one and to use pythagoream thereom ....a^2+b^2=c^2 Hey but seriously if you got lost you could use something like this to arrive home safely. lol 6k. It's a simple 3-4-5 right triangle. OK, Cruising, here's one for you, and only you (so all you wily types hush up): You head out to look for my new multi-cache. After arriving at the posted coordinates, you find instructions telling you to walk 1km DUE SOUTH to the next waypoint. This waypoint instructs you to walk 1km DUE EAST to find the next waypoint. At this waypoint, you are told to walk 1km DUE NORTH, which you then do. Amazingly, you find yourself at exactly the same place you started. How is this possible? actually you would be 1 km of to the EAST from the starting position. 1km l l 1km l l ------------ 1km tried to edit for my stupid box i made but hopefully tou get the point? I wasn't asking where you would be. I was TELLING you that you're exactly where you started. You started at a waypoint (call it point A). You went 1km south. Then 1km east. Then 1km north. You somehow found yourself back at point A. NOT 1km east, but exactly where you started at, at point A. My question was not where, but how? Oh yeah, and what color WAS the bear that you saw there? Quote Link to comment
+huskerrich2000 Posted November 15, 2005 Share Posted November 15, 2005 well you knew that was a big patch of poison oak when you walked eight miles north, remember the distance around the right angle has to be further than a straight walk (10miles) Quote Link to comment
+Stunod Posted November 15, 2005 Share Posted November 15, 2005 (edited) I wish I could have posted my high school physics homework on the web and had people do it for me. Would have left more time for girls. Edited November 15, 2005 by Stunod Quote Link to comment
+worldtraveler Posted November 15, 2005 Share Posted November 15, 2005 White. The bear was definitely white. Quote Link to comment
Cruising_Adventuring Posted November 16, 2005 Author Share Posted November 16, 2005 I wish I could have posted my high school physics homework on the web and had people do it for me. Would have left more time for girls. lol! good idea! Quote Link to comment
Cruising_Adventuring Posted November 30, 2005 Author Share Posted November 30, 2005 bump (in reply to my post in sept1c's puzzle cache question. Quote Link to comment
+Jellyfishman Posted November 30, 2005 Share Posted November 30, 2005 What if the wrench falls in the woods and there is no one there to hear it? Let your precious math figure that one out! Jelly Quote Link to comment
Cruising_Adventuring Posted November 30, 2005 Author Share Posted November 30, 2005 Well then 4564x10x-4Fn+Fma=ummmm I dont know? lol Quote Link to comment
+TeamGuisinger Posted November 30, 2005 Share Posted November 30, 2005 Better make sure that's not an aluminum wrench. Quote Link to comment
+jadeskyline Posted November 30, 2005 Share Posted November 30, 2005 That's easy... The answer is "Indiana" i don't get it. Quote Link to comment
Cruising_Adventuring Posted November 30, 2005 Author Share Posted November 30, 2005 Better make sure that's not an aluminum wrench. lol Quote Link to comment
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