difference in feet

[+bigbill6]

please tell me what the diff.would be...in feet .say from a cords reading of 41 17.358 to 41 17.340....thank you

[Kerry.]

About 110'

 

Cheers, Kerry.

 

I never get lost everybody keeps telling me where to go

[Kerry.]

About 110'

 

Cheers, Kerry.

 

I never get lost everybody keeps telling me where to go

[SC-Yankee]

Each second equals @ 6.11 feet? Is that correct? Inquiring minds would like to know:D. This is based on the latest known circomfrence of the planet divided by 360 (1deg)divided by 60 (1min) divided by 60 (1sec) is that about right? Is there a table listed somewhere? Thanks

 

[This message was edited by SC-Yankee on August 08, 2002 at 03:09 PM.]

[SC-Yankee]

Each second equals @ 6.11 feet? Is that correct? Inquiring minds would like to know. This is based on the latest known circomfrence of the planet divided by 360 (1deg)divided by 60 (1min) divided by 60 (1sec) is that about right? Is there a table listed somewhere? Thanks

 

[This message was edited by SC-Yankee on August 08, 2002 at 03:09 PM.]

[+BillP3rd]

The distance between degrees of latitude can only be calculated in a strictly north-south line. Lines of latitude are equaly spaced apart their entire length. This is NOT true for lines of longitude, however. Lines of longitude get closer together as you approach the poles.

 

Some useful numbers for your calculations:

 

1 minute of latitude = 1 nautical mile

1 nautical mile = 6076.11549 feet (appx.)

 

Hence:

 

1 second = 101.2684 feet (101' 3.2")

1 thousandth of a minute = 6.0761 feet (6' 0.9")

 

To your original question, without the longitude you can't know the distance between the points. You could walk about 109 feet straight south and you'd be at the desired latitude (41 17.340).

[+EraSeek]

Here you go:

 

http://home.online.no/~sigurdhu/Grid_1deg.htm

 

[+EraSeek]

109.30511'

[SC-Yankee]

Thanks Eraseek, the table answers a lot.

[+bigbill6]

thanks...all of you....this has been a big help