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Most saturated OS Sq Km


Mallah

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Hopefully I might have a look at this later today, maybe while I'm watching the Ireland/France match.

Work got in the way yesterday afternoon, and again today, and I'm out caching tomorrow. I have come up with a simple algorithm, if I get 10 minutes I'll code it up and leave it running tomorrow while I'm out - it's likely to take longer than the original question.

 

Does this do what you wanted?

 

1) Create temporary integer columns Group and GroupStatus, initialise all rows to 0. Group will be used to identify all caches in one interconnected group, i.e. where all the caches in the group are less than 2 minimum separation distances from any other in the group. Group Status will be used only during the computation, 0 means unprocessed, 1 means unprocessed high priority, 2 means processed.

2) Pick any cache where GroupStatus=0. If there are none left, it's finished.

3) Increment the Group number.

4) Set the selected cache Group to the current Group number, and GroupStatus to 2.

5) For all caches within 2 minimum separation distances, and for which GroupStatus is still 0, set Group to the current Group number, and GroupStatus to 1.

6) Select any cache where GroupStatus=1. If there are none go to 2.

7) Set GroupStatus to 2.

8) Go to 5.

 

This doesn't get as far as calculating the area. There may be an elegant mathematical solution to that, but I don't know it. I'll probably kludge it by plotting the circles onto a bitmap and counting the pixels.

 

RGds, Andy

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Comments inline ...

 

1) Create temporary integer columns Group and GroupStatus, initialise all rows to 0. Group will be used to identify all caches in one interconnected group, i.e. where all the caches in the group are less than 2 minimum separation distances from any at least one other in the group. Group Status will be used only during the computation, 0 means unprocessed, 1 means unprocessed high priority, 2 means processed.

2) Pick any cache where GroupStatus=0. If there are none left, it's finished.

3) Increment the Group number.

4) Set the selected cache Group to the current Group number, and GroupStatus to 2.

5) For all caches within 2 minimum separation distances of the cache whose GroupStatus you've just set to 2, and for which GroupStatus is still 0, set Group to the current Group number, and GroupStatus to 1.

6) Select any cache where GroupStatus=1. If there are none go to 2.

7) Set GroupStatus to 2.

8) Go to 5.

 

I've got essentially the same (except it's implemented recursively) in R, together with what is getting pretty close to being an exact calculation of the area. The code assumes a flat Earth; I couldn't face coding the distance calculations properly. I don't have the full set of UK waypoints, though, so I'm probably not going to run the code for real - and, anyway, R is slooow.

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Comments inline ...

Your comments are as I intended it to read.
I've got essentially the same (except it's implemented recursively)
Mine isn't coded like that - I intended it to be a simpler description for non-programmers.
The code assumes a flat Earth; I couldn't face coding the distance calculations properly.
As the separation in distance calculations is not more than (just under) 322 metres, not using a great circle distance should introduce an almost immeasurably small error. If you mean you use a 2D projection it may introduce a percent or two.

 

I'm nearly ready for tomorrow, so I'll knock up the first part this evening and run it overnight. As I'm up and about much earlier than my caching buddy I'll probably have an answer to "what's the island-of-exclusion ("Group") with the greatest number of caches?" before I go out.

 

Rgds, Andy

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I'm nearly ready for tomorrow, so I'll knock up the first part this evening and run it overnight. As I'm up and about much earlier than my caching buddy I'll probably have an answer to "what's the island-of-exclusion ("Group") with the greatest number of caches?" before I go out.

Number of caches in group, OS grid ref SW, OS grid ref NE (the bounding rectangle is for the caches, not the exclusion zone, but it's enough to tell you where to look).

 

162 570111,205428 584679,209517

159 366593,303795 370544,312264

94 263230,145177 268091,148288

89 530978,180028 534347,182282

82 578902,109135 582974,111237

82 492855,202254 497863,205395

74 373109,302595 376247,306837

74 361603,312202 365305,315586

73 523633,153391 527712,156869

70 516140,148643 520050,151763

 

The first one has Chelmsford on its west side, and largely comprises the west end of the Chelmer powertrail plus a load of caches in Chelmsford itself. Had there not been a break in the powertrail at Hoe Mill Barns, it would have been considerably larger.

 

The second is at Telford.

 

These are numbers of caches, not area. I suspect the Telford group will have the larger area because the caches along the Chelmer are mostly are at the minimum separation distance whereas the Telford ones mostly are further apart.

 

The gap between 2 and 3 is such that I suspect the others won't come into play.

 

I'll do the areas some other time, but it won't be today.

 

Rgds, Andy

Edited by Amberel
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I've been pestering Andy for various datasets so that I can do the area calculation. You'll be thrilled, I'm sure, to learn that we're ready to share the results.

 

Andy's search parameters:

Groundspeak only, 10 Mar 2012
Include traditional, multi, letterbox, unknown, Wherigo
Exclude virtual, earthcache, webcam, events, all remaining cache types
Include temp disabled, exclude archived

Results:

 Nr |  Area   | Area/Nr | Density |  SW grid ref  | NE grid ref
----+---------+---------+---------+---------------+--------------
162 | 110.330 | 0.68105 | 0.89775 | 570111,205428 | 584679,209517
159 | 108.051 | 0.67956 | 0.89978 | 366593,303795 | 370544,312264
94 |  68.924 | 0.73323 | 0.83624 | 263230,145177 | 268091,148288
84 |  66.114 | 0.78707 | 0.77966 | 492855,202254 | 497958,205395
82 |  57.256 | 0.69824 | 0.87902 | 578902,109135 | 582974,111237
74 |  54.647 | 0.73847 | 0.83183 | 361603,312202 | 365305,315586
74 |  49.756 | 0.67237 | 0.91360 | 530978,180028 | 534347,182282
74 |  55.104 | 0.74465 | 0.82493 | 373109,302595 | 376247,306837
72 |  52.175 | 0.72466 | 0.84789 | 523633,153511 | 527712,156869
66 |  47.879 | 0.72545 | 0.84765 | 548411,163060 | 551865,165981

Key:

     Nr = number of caches in the group
  Area = number of 0.1-mile disks (equivalent) area covered by the caches
Area/Nr = as it says
Density = how much more tightly packed the group is compared to a maximally
         compressed linear powertrail of the same length (<1 = less packed)

 

So now you know.

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