andylphoto Posted January 6, 2009 Share Posted January 6, 2009 I have looked briefly for RL0161 without success. I did only a brief search while in the area searching for other stations. I wasn't expecting success with the time I had. I did not have my metal detector, and the area had been logged within the past few years, leaving many brush piles. I also realized later that I actually misread the description on my first search attempt. Now, however, I'm not entirely sure where to measure from. AT THE OUTSIDE OF A LONG CURVE WITH TANGENTS SOUTH AND NORTHWEST, ABOUT 125 YARDS NORTHWEST OF THE SOUTHEAST END OF THE NORTHWEST TANGENT OF CURVE So my question is about where the SE end of the NW tangent would be, exactly. I've got two ideas that both seem plausible to me, and I wanted to get a consensus before I try another search in the spring. Would the SE end of the NW tangent be... 1. The point at which the straight-line portion of the road (NW/SE) begins its curve to the south, or 2. The point of intersection of the extended center lines of the NW and South tangents of the road described. The first would be (geometrically speaking) the point of intersection of the line representing the NW tangent and the circle, a portion of which makes up the curve in the roadway. The second would be the point of intersection of both tangents, and would mark a point off the roadway, near the center of the curve. The first would seem to me to make more sense, but then the placement of the station would then be well into the straight portion of the roadway, and would seem to be better described as "NW OF A LONG CURVE..." rather than "AT THE OUTSIDE OF A LONG CURVE..." When I read the latter, it seems to place the station at some point between the ends of the curve. I would guess that the boulder described later in the data sheet is probably still present, but getting started searching in the right area is always a good thing. I found a boulder during my search in the wrong area that seemed to match the description too. Thanks for any input! Quote Link to comment
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