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Simply Paul

The All New All New Groundspeak UK Pub Quiz

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As we are entering the festive season. How many legs are there in the twelve days of Christmas?

 

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No idea, now I cant get the song out of my head.

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After singing the song over and over again and using Excel to count everything up I come up with 808 legs.

Edited by speakers-corner
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On 12/8/2017 at 3:22 AM, speakers-corner said:

After singing the song over and over again and using Excel to count everything up I come up with 808 legs.

I also came up with 808 (assuming the eight maids are a-milking one four-legged beast each), but I'll add me and my true love and say 812.

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I've been trying to get rid of this earworm but it's been reinforced at every seasonal event I have attended.

So, let's try again with 976.

 

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880 . You didn' t say the legs had to be animate, and I'm assuming the maids 'milking stools were 3 legged ones.

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OK, sometimes you have a boring wait to occupy, and I've reached an impasse withh the puzzle cache I'm banging my head against, so I went through and revised my calculations for this, having realised I'd only added in the milking stools the once. So, as my grammar school training always insisted in exams you must 'show your working'  here goes : best read from the bottom to top
day 12 = 182+24 = 206   (day 11 plus twelve lords a leaping)
day 11 = 160+22 = 182   (day 10 plus eleven ladies)
day 10 = 140+20 = 160   (day 9 plus 20 for ten pipers)
day  9 = 122+18 = 140   (day 8 plus 18 for  nine drummers)
day  8 = 50+72   = 122   (day 7 plus 8 maid/cow/milking stool combos, 9 legs per)= 72)
day  7 = 36+14    =  50   (day 6 plus 14 for seven swans)
day  6 = 24+12    =  36   (day 5 plus 12 for Six geese)

day  5 =                  24    gold rings,same legs as day 4
day  4 =   16+8  =   24    (day 3 plus 8 for four colly birds)
day  3 =   10+6  =  16    (day 2 plus 6 for three fench hens)
day  2 =   6+4   =   10    (day 1 plus 4 for two turtle doves)
Day  1 = 2+2+2   =  6    (me,my true love + one partridge)

                   Total = 976

So, my new answer is 976.

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 Or. if inanimate legs are disallowed ( and assuming none of the lords a leaping are drunk as lords, i.e. legless )

day 12 = 158+24=  182 (day 11 plus twelve lords a leaping)
day 11 = 136+22 = 158 (day 10 plus eleven ladies)
day 10 = 116+20 = 136   (day 9 plus 20 for ten pipers)
day  9 =  98+18 = 116 (day 8 plus 18 for  nine drummers)
day  8 = 50+48  =  98   (day 7 plus 8 maid/cow combos,6 legs per)=48)
      Giving a  total without milking stools = 856

I think I need a lie down now.

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Hal-an-tow, the problem with your method is that it adds me and my true love on every day of Christmas. Although they (we?) are mentioned 12 times, I think it is safe to assume that there is only one true love, and certainly only one of me.

So revising your incremental method gives

Day 1 = 2

Day 2 = 2+(2x2) = 2+4 = 6

Day 3 = 6+(3x2) = 6+6 = 12

Day 4 = 12+(4x2) = 12+8 = 20

Day 5 = 20+(5x0) = 20+0 = 20

Day 6 = 20+(6x2) = 20+12 = 32

Day 7 = 32+(7x2) = 32+14 = 46

Day 8 = 46+(8x9) = 46+72 = 118 (assuming 8 milkmaids, 8 cows and 8 three-legged stools)

Day 9 = 118+(9x2) = 118 + 18 = 136

Day 10 = 136+(10x2) = 136+20 = 156

Day 11 = 156+(11x2) = 156+22 = 178

Day 12 = 178+(12x2) = 178+24 = 202

Total = 928, plus me and my true love = 932.

 

If you ignore the milking stools, the last five days becomes

Day 8 = 46+(8x6) = 46+48 = 94

Day 9 = 94+(9x2) = 94+18 = 112

Day 10 = 112+(10x2) = 112+20 = 132

Day 11 = 132+(11x2) = 132+22 = 154

Day 12 = 154+(12x2) = 154+24 = 178

Total = 808, plus me and my true love = 812 as stated earlier.

 

Boggin's Dad, have any of us hit the target yet?

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Ah, a debate on semantics, that could easily run to a dozen pages of intemperate shouting if this wasn't a civilised area ... :laughing:

If the " first person plus beloved" characters appear in each verse, and we assume they are the same individuals each day, how can we say the same french hens etc etc are not also re-deployed each day ? I can't tell chickens apart*, you could easily fool me by claiming these were entirely different to yesterdays fowl ...same for the other birds, none of which has the distinctive individually varied plumage which identifies budgies for instance  ...

Also, the initial question said ' How many legs ' , not how many different legs, so same beloved, same legs, different day = 2 more legs in the song  :lol:

I rest my case, (while suggesting that the problem lies with the phrasing of the question) and await the final authoritative verdict of the questioner (who is probably weeping softly over a calculator as I type) .

 

 

^ As an afterthought, I have farmer friends who have some rescued battery hens clucking round their yard, one of who (inevitably named 'Stumpy' ) I can distinguish from the rest,  but only because she would ruin the leg count with 1 .5 to her name  ... pretty sure she is not French though ....

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I am going to have to give this one to searcherdog, but a close second and congratulations to Hal-an-tow for getting full marks, as he showed all his working

My intitial sum led me to 928 - I was including the milking stool, but then had not added in me, and my true love....

So the answer I am going to judge as right is 976 which includes those extra 48 legs.

Well done searcherdog A very festive ding for you - Over to you

 

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20 hours ago, hal-an-tow said:

She showed all her working actually :D

I think I have fallen foul of that one before..... :huh:

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